write an equation line tangent curve x y

didn’t even bother reviewing the results.) As stated, a new host and get your sites up soon. Wishing you good luck in getting theusage is what matters —

The equation of the line tangent to the curve x^2 + y^2 = 25 at the point (3, -4) has to be determined.The slope of the line is equal to the value of `dy/dx` at the point (3, -4)Using implicit differentiation gives:`2x + 2y*(dy/dx) = 0`=> `dy/dx = -x/y`At the point (3, -4)`dy/dx = -3/-4 = 3/4`The equation of the tangent is `(y + 4)/(x – 3) = 3/4`=> 4y + 16 = 3x – 9=> 3x – 4y – 25 = 0The equation of the tangent to the curve x^2 + y^2 = 25 at (3, -4) is 3x – 4y – 25 = 0

write an equation line tangent curve x y

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