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find value k that lines perpendicular

find value k that lines perpendicular
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You need to write the parametric equations of the lines `d_1`  and `d_2`  such that:`x_1 = 3 + (3k+1)*t“y_1 = -6 + 2t“z_1 = -3 + 2k*t“x_2 = -7 + 3s“y_2 = -8 – 2ks“z_2 = -9 – 3s`You need to write the vector lines such that:`bar d_1 = lt3,-6,-3gt + t*lt(3k+1,2,2k)gt“bar d_2 = lt-7,-8,-9gt + s*lt3,-2k,-3gt`The lines `d_1`  and `d_2`  are perpendicular if the dot product `bar d_1*bar d_2 = 0`  such that:`lt(3k+1,2,2k)gt*lt3,-2k,-3gt = 0“3k + 1 = 3=gt k_1 = 2/3“-2k=2 =gt k_2 = -1“2k=-3 =gt k_3 = -3/2`Hence, evaluating the values of k for the lines are perpendicular yields `k_1 = 2/3,k_2 = -1,k_3 = -3/2.`
find value k that lines perpendicular

  and x-3 / 3k+1 = y+6/2= z+3/2k  and x+7/3 = y+8/-2k = x+9/-3 SOrry those are the equations. Forgot to put them up